Answer:13.2 m/s
Explanation:
Given
mass of sam[tex]\left ( m\right )=78 kg[/tex]
Thrust force=180 N
coefficient of kinetic friction[tex](\mu _k)=0.1[/tex]
Force acting on sam is thrust force, friction force
[tex]f_r=\mu _kmg=0.1\times 78\times 9.8=76.44 m/s[/tex]
[tex]F_{thrust}-f_r=ma[/tex]
[tex]180-76.44=78\times a[/tex]
[tex]a=1.32 m/s^2[/tex]
Therefore its top speed is
v=u+at
here u=0 initial velocity
[tex]v=0+1.32\times 10=13.2 m/s[/tex]
