Answer: 5040
Step-by-step explanation:
Given : Number of choices to make a four digit code ( 0 to 9)= 10
If repetition is not allowed , then we use Permutations to find the number of different code groups can be designed.
The number of permutations of n things , taking r at a time is given by :-
[tex]^nP_r=\dfrac{n!}{(n-r)!}[/tex]
Then, the number of permutations of 10 numbers , taking 4 at a time is given by :-
[tex]^{10}P_{4}=\dfrac{10!}{(10-4)!}\\\\=\dfrac{10\times9\times8\times7\times6!}{6!}\\\\=\dfrac{10\times9\times8\times7}{1}\\\\=5040[/tex]
Hence, the number of different code groups can be designed= 5040