For a club, initiation price is $125 and monthly fee is 17.50 per month. A second club has a monthly fee of $23. How many months will take for the fee of the second club to cost more than the first?

For a club initiation price is 125 and monthly fee is 1750 per month A second club has a monthly fee of 23 How many months will take for the fee of the second c class=

Respuesta :

Answer: m= 25

Step-by-step explanation: m= # of months in a club

The Equation is 17.50m + 125 =  23m

                         -17.50m            -17.50m

                                       125  = 5m

                                    125/5   = 5m/5

                                           25= m

                                           m= 25

Answer:

The second club will take approximately 15 months

Solution:

Given that the initiation fees for the first club is $125.  

Monthly fees for the first club = $17.50 per month.

Annual fees for the first club = [tex]($17.50 \times 12)[/tex]

= $210

Total fees for the first club = $210+$125

= $335

Now, For the second club there is no initiation fees.

Monthly fees for the second club = $ 23

Annual fees for the second club = [tex]($23 \times 12)[/tex]

= $276

The difference between the annual fees of the first and the second club is ($335 - $276) = $59

So to cover $59 , the second club will take

[tex]\frac{59}{23}=2 \frac{1}{23}[/tex]

Thus the second club will take [tex]12 + 2 \frac{1}{23} = 14.566 = 15[/tex] months to cost more than the first.