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May rides her bike the same distance that Leah walks. May rides her bike 10 km/h faster than Leah walks. If it takes May 1 hour and Leah 3 hours to travel that distance, how fast does each travel

Respuesta :

fareizzy

May DATA:

time = 1 hr. ; rate = x+10 mph ; distance = rt = (x+10)*1 mi

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Leah DATA:

time = 3 hr. ; rate = x mph ; distance = rt = 3x mi

Equation:

distance = distance

x+10 = 3x

2x = 10

x = 5 mph (Leah's rate)

x+10 = 15 mph (May's rate)

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