The Total Suspended Solids for a wastewater sample was found to be 175 mg/L If the following test results were obtained, what size sample was used in the analysis? Tare mass of gass fiber filter = Residue on glass fiber filter after drying at 105°C = 1.5413 g 1.5538 g

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valetta valetta · Answer 1 · 2019-10-10T07:49:34+02:00

Answer:

Volume of the sample = 0.0714 L

Explanation:

Given:

Total Suspended Solids for a wastewater sample = 175 mg/L

Tare Mass of glass fiber filter = 1.5413 g

Residue on glass fiber filter after drying at 105°C = 1.5538 g

Now,

The mass collected on the filter

= Residue on glass fiber filter after drying - Tare Mass of glass fiber filter

= 1.5538 - 1.5413

= 0.0125 grams

= 0.0125 × 1000 = 12.5 mg

Also,

Concentration of the solids in water = [tex]\frac{\textup{Mass collected on the filter}}{\textup{Total volume of the sample}}[/tex]

or

175 mg/L = [tex]\frac{\textup{12.5 mg}}{\textup{Total volume of the sample}}[/tex]

or

Volume of the sample = [tex]\frac{\textup{12.5}}{\textup{175}}[/tex]

or

Volume of the sample = 0.0714 L