Respuesta :
Answer : The mass of sodium are there in a 102-g sample of the substance are 14.28 grams.
Explanation: Given,
Mass of sodium = 23.0 g
Mass of aluminum = 27.0 g
Mass of fluorine = 114 g
Total mass of sample = 102 g
Total mass of substance = Mass of sodium + Mass of aluminum + Mass of fluorine
Total mass of substance = 23.0 + 27.0 + 114 = 164 g
Now we have to calculate the mass fraction of sodium.
[tex]\text{ Mass fraction of sodium}=\frac{\text{Mass of sodium}}{\text{Total mass of substance}}[/tex]
[tex]\text{ Mass fraction of sodium}=\frac{23.0g}{164g}=0.140[/tex]
Now we have to calculate the mass of sodium are there in a 102-g sample of the substance.
[tex]\text{Mass of sodium}=0.140\times 102=14.28g[/tex]
Therefore, the mass of sodium are there in a 102-g sample of the substance are 14.28 grams.
The mass of sodium, Na in 102 g sample of the substance is 14.28 g
We'll begin by calculating the mass fraction of sodium, Na in the sample. This can be obtained as follow:
Mass of Na = 23 g
Mass of Al = 27 g
Mass of fluorine = 114 g
Total mass = 23 + 27 + 114
Total mass = 164 g
Mass fraction of Na =?
[tex]Mass fraction = \frac{mass of element}{total mass } \\\\= \frac{23}{164}\\\\[/tex]
= 0.140
- Finally, we shall determine the mass of sodium, Na in 102 g of the sample. This can be obtained as follow:
Mass fraction of Na = 0.140
Mass of sample = 102 g
Mass of Na =?
Mass of element = mass fraction × mass of sample
Mass of Na = 0.140 × 102
Mass of Na = 14.28 g
Therefore, the mass of sodium, Na in 102 g of the sample is 14.28 g
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