Mike's car, which weighs 1,000 kg, is out of gas. Mike is trying to push the car to a gas station, and he makes the car go 0.05 m/s2. Using Newton's Second Law, you can compute how much force Mike is applying to the car.

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Answer:

The answer to your question is: F = 50 N

Explanation:

Data

mass = 1000 kg

acceleration = 0.05m/s2

F = ?

Formula

F = m x a

Substitution

F = 1000 kg x 0.05 m/s2 = 50 kgm/s2 = 50 N

Mike is applying a force of 50 N to the car.

The magnitude of applied force on the car by Mike is 50 N.

Given data:

The mass of car is, m = 1000 kg.

The magnitude of acceleration of car is, [tex]a = 0.05 \;\rm m/s^{2}[/tex].

According to Newton's second law of motion, the force applied on the object is expressed as the product of mass of object and magnitude of acceleration caused by the applied force on the object.

Therefore,

[tex]F = m \times a[/tex]

Here, F is magnitude of applied force on car.

Solving as,

[tex]F = 1000 \times 0.05\\F = 50 \;\rm N[/tex]

Thus, we can conclude that Mike is applying 50 N of force on his car.

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