Answer:
Double the charge to 2Q
Explanation:
The magnitude of a electric field caused by a charge Q at a distance R can be find by the following expression:
[tex]E = K\frac{Q}{R^2}[/tex]
Where K is the Coulomb constant.
As the relationship between the charge and the electric fiel is proportional, by simply doubling the charge, you would double the magnitude of the electric field.
Notice that the distance affects the magnitude of the electric field by the inverse square. So if you half the distance, the magnitude of the field will quadruple.
It is a physical field occupied by a charged particle on another particle in its surrounding. In order to double the megnitude at point P . You can double the charge to 2Q or reduce the distance to R/2.
It is a physical field occupied by a charged particle on another particle in its surrounding.
The relation of the electric field with the distance between the charged particle is given by the formula.
[tex]E= \frac{ KQ }{R^{2} }[/tex]
Where R is the spacing between the point charge
Electric field intensity is inversly proportional to the square of the distance.
Hence by doubling the charge to 2Q or reducing the distance to R/2. The megnitude of the field P can be doubled.
To learn more about the electric force refer to the link;
brainly.com/question/1076352
