Answer:
TH=14.56
Step-by-step explanation:
Given: T(10,7) and H(-4,3)
Distance formula: [tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
[tex]\text{Length of TH }=\sqrt{(-4-10)^2+(3-7)^2}[/tex]
[tex]=\sqrt{14^2+4^2}[/tex]
[tex]=\sqrt{196+16}[/tex]
[tex]=\sqrt{212}[/tex]
[tex]\approx 14.56[/tex]
Hence, The length of TH [tex]\sqrt{212}\approx 14.56[/tex]
