Answer:
Volume of [tex]62[/tex] % acid solution is [tex]34.878 mL[/tex]
Explanation:
The total weight of [tex]34[/tex] % mixture containing [tex]62[/tex] % and [tex]21[/tex] % solutions [tex]= 110[/tex] mL
Let the weight of [tex]62[/tex] % solution is equal to [tex]X[/tex] mL
then the weight of [tex]21[/tex] % solution is equal to [tex]110-X[/tex] mL
Arranging the given conditions in the form of equation, we get -
[tex]0.62 X + 0.21 (110 -X) = 0.34 * 110[/tex]
[tex]0.62 X + 23.1 - 0.21 X = 37.4\\0.62 X - 0.21 X = 37.4 - 23.1\\X = \frac{14.3}{0.41} \\X = 34.878[/tex] mL
The volume of [tex]62[/tex] % acid solution is [tex]34.878 mL[/tex]