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Sarah begins at a negative position along the x-axis. Sarah moves in the positive x-direction, turns around and then moves in the negative x-direction. Her final position is more negative that her initial position. Is the magnitude of Sarah's displacement greater than, less than, or equal to the distance she travels?

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horaciocrotte

Answer:

he magnitude of Sarah's displacement is less than the distance she travels

Step-by-step explanation:

Hi!

The magnitude of her displacement is just the difference between her final and initial state, however the distance she traveled is two times the distance she moved in the positive x-direction until she turned around, since she had to move back, plus her displacement.

So:

[tex]displacement = |x_{final} -x_{initial}| \\distanceTraveled = 2|x_{return}-x_{initial}| + displacement\\[/tex]

Since all the terms are positive:

[tex]x_{displacement}<x_{traveled}[/tex]

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