Vector C has a magnitude of 22.2 m and points in the −y‑ direction. Vectors A and B both have positive y‑ components, and make angles of α=41.9° and β=28.2° with the positive and negative x- axis, respectively. If the vector sum A+B+C=0 , what are the magnitudes of A and B?

Respuesta :

Answer:

The magnitude of A is 17.46 m and B is 1.50 m

Step-by-step explanation:

If the vector sum A+B+C =0, then the sum of the projection of the vector in axes x- is zero and the sum of the projection of the vector in the axes y- is also zero.

Ax+Bx+Cx = 0

Ay+By+Cy = 0

|Ax| = cos 41.9 * |A|

|Ay| = sin 41.9 * |A|

|Bx| = cos 28.2 * |B|

|By| = sin 28.2 * |B|

|Cx| = 0

|Cy| = 22.2

Ax+Bx+Cx = 0

|Ax|-|Bx|+0 =0

the vector Ax is in the positive direction of the x- axes and Bx in the negative direction and C do not have a component in the x- axes

cos 41.9 * |A| - cos 28.2 * |B| = 0 (I)

Ay+By+Cy = 0

|Ay|+|By|-|Cy|=0

the vector Ay and By are the positive direction of the y- axes and Cy in the negative direction

sin 41.9 * |A| + sin 28.2 * |B| - 22 =0 (II)

Now we have a system of 2 (I and II) equations and 2 variables (|A| and |B|)

cos 41.9 * |A| - cos 28.2 * |B| = 0

sin 41.9 * |A| + sin 28.2 * |B| = 22

cos 41.9 * |A| = cos 28.2 * |B|

|A| = cos 28.2 * |B| / cos 41.9

sin 41.9 * |A| + sin 28.2 * |B| = 22

sin 41.9 *  cos 28.2 * |B| / cos 41.9 + sin 28.2 * |B| = 22

tg 41.9 * cos 28.2 * |B| + sin 28.2 * |B| = 22

(tg 41.9 * cos 28.2 + sin 28.2) * |B| = 22

|B| = 22 / (tg 41.9 * cos 28.2 + sin 28.2)

|B| = 17.46

|A| = 1.50

The magnitude of vector A and the magnitude of vector B is 20.6198 and 17.4146 respectively.

What is a vector?

The quantity which has magnitude, direction and follows the law of vector addition is called a vector.

Given

Vector C has a magnitude of 22.2 m and points in the negative y‑direction.

Vectors A and B both have positive y‑components and make angles of α=41.9° and β=28.2° with the positive and negative x-axis.

Let the vectors A, B, and C be concurrent.

Then vectors can be resolved in x-direction and y-direction.

Vectors in y-direction

[tex]\rm A\ sin 41.9^o + B \ sin28.2^o = C\\0.6678\ A\ \ +\ 0.4726\ B \ = 22[/tex].....eq(1)

Vectors in x-direction

[tex]\rm A \ cos41.9^o = B \ cos 28.2^o\\0.74431 \ \ A = B \ \ 0.8813[/tex].....eq(2)

From equations 1 and 2, we get

A = 20.6199 and B = 17.4147

Thus, the magnitude of vector A and the magnitude of vector B is 20.6198 and 17.4146 respectively.

More about the vector link is given below.

https://brainly.com/question/13188123