Answer:
[tex]x^2-36=0[/tex]
Step-by-step explanation:
Solution is 6 and -6. Lets check with each option
[tex]x^2-12x+36=0[/tex]
[tex](x-6)(x-6)=0[/tex]
x-6=0 so x=6
Solutions are 6 and 6. First option does not gives us solution 6 and -6
[tex]x^2+12x-36=0[/tex]. It is not factorable
[tex]x^2+36=0[/tex]. It is not factorable
[tex]x^2-36=0[/tex]
[tex](x+6)(x-6)=0[/tex]
x-6=0 , so x=6
x+6=0, so x=-6
[tex]x^2-36=0[/tex] is the final answer
