Answer: He burned 800 calories per hour playing basketball.
Step-by-step explanation:
Let be "b" the amount of calories per hour Jason burned playing basketball and "c" the amount of calories per hour Jason burned canoeing.
Set up a system of equations:
[tex]\left \{ {{b+2c=1,400} \atop {2b+3c=2,500}} \right.[/tex]
You can apply Elimination Method:
Therefore, you get:
[tex]\left \{ {{-3b-6c=-4,200} \atop {4b+6c=5,000}} \right.\\.............................\\b=800[/tex]