Answer:
(a) [tex] X=2000m[/tex]
(b) [tex]Y=1920m[/tex]
(c) [tex]v=175.3m/s[/tex]
(d) [tex]a=7.6m/s^2[/tex]
Explanation:
[tex]x=1.25 t^2 [/tex]
and
[tex]y=0.03 t^3[/tex]
Kinematics formules:
[tex]v_{x}=dx/dt=2.5t\\[/tex]
[tex]a_{x}=dv_{x}/dt=2.5\\[/tex]
[tex]v_{y}=dy/dt=0.09t^2\\[/tex]
[tex]a_{y}=dv_{y}/dt=0.018t\\[/tex]
at T=40s:
(a) [tex] X=1.25*(40)^2=2000m[/tex]
(b) [tex]Y=0.03*(40)^3=1920m[/tex]
(c) [tex]v=\sqrt{v_{x}^2+v_{y}^2} =\sqrt{(2.5*40)^2+(0.09*40^2)^2} =175.3m/s[/tex]
(d) [tex]a=\sqrt{a_{x}^2+a_{y}^2} =\sqrt{(2.5)^2+(0.18*40)^2} =7.6m/s^2[/tex]
