Answer:
[tex]\boxed{39}[/tex]
Step-by-step explanation:
[tex]\begin{array}{rcc}& \textbf{Archery Sign Up} & \textbf{Total Campers}\\\textbf{Week 1} & 36 & 120\\\textbf{Week 2} & 45 & 150\\\textbf{Week 3} & ? & 130\\\end{array}[/tex]
Let x = Total campers
and y = Archery sign up
In a direct proportionality,
y = kx
1. Calculate the value of k
Substitute a pair of values for x and y
150 = k × 45
Divide each side by 45
k = 150/45 = 10/3
2. Calculate the value of x in Week 3
[tex]\begin{array}{rcl}130& = & \dfrac{10}{3}x\\\\390 & = & 10x\\x & = & \mathbf{39}\\\end{array}[/tex]
[tex]\boxed{\textbf{39 campers}} \text{ will sign up for archery in Week 3}[/tex]
The diagram is a graph of your proportionality. It shows that y = 130 when x = 39.
