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The position of a particle moving under uniform acceleration is some function of time and the acceleration. Suppose we write this position as x = kamtn, where k is a dimensionless constant. Show by dimensional analysis that this expression is satisfied if m = 1 and n = 2. (Submit a file with a maximum size of 1 MB.)

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Answer:

Explanation:

[tex]x = k\times a^m\times t^n[/tex]

k is constant , it is dimension is zero. Using dimensional unit , we cal write the relation as follows

L = [tex](LT^{-2})^m(T)^n[/tex]

= [tex]L^mT^{-2m+n}[/tex]

Equating power of like items

m=1

-2m+n = 0

n = 2

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