The partial pressure of CO2 gas above the liquid in a carbonated drink is 0.71 atm. Assuming that the Henry's law constant for CO2 in the drink is that same as that in water, 3.7 x 10-2 mol/L atm, calculate the solubility of carbon dioxide in this drink. Give your answer to 3 decimal places.

Respuesta :

Answer: The molar solubility of carbon dioxide gas is 0.003 M

Explanation:

Henry's law states that the amount of gas dissolved or molar solubility of gas is directly proportional to the partial pressure of the liquid.

To calculate the molar solubility, we use the equation given by Henry's law, which is:

[tex]C_{CO_2}=K_H\times p_{liquid}[/tex]

where,

[tex]K_H[/tex] = Henry's constant = [tex]3.7\times 10^{-2}mol/L.atm[/tex]

[tex]p_{CO_2}[/tex] = partial pressure of carbonated drink = 0.71 atm

Putting values in above equation, we get:

[tex]C_{CO_2}=3.7\times 10^{-2}mol/L.atm\times 0.71atm\\\\C_{CO_2}=2.637\times 10^{-2}mol/L=0.003M[/tex]

Hence, the molar solubility of carbon dioxide gas is 0.003 M

Answer: The molar solubility of carbon dioxide is [tex]2.63\times 10^{-2}M[/tex]

Explanation:

To calculate the molar solubility, we use the equation given by Henry's law, which is:

[tex]C_{CO_2}=K_H\times p_{CO_2}[/tex]

where,

[tex]K_H[/tex] = Henry's constant = [tex]3.7\times 10^{-2}mol/L.atm[/tex]

[tex]C_{CO_2}[/tex] = molar solubility of carbon dioxide gas = ?

[tex]p_{CO_2}[/tex]  = partial pressure of carbon dioxide gas = 0.71 atm

Putting values in above equation, we get:

[tex]C_{CO_2}=3.7\times 10^{-2}mol/L.atm\times 0.71atm\\\\C_{CO_2}=2.63\times 10^{-2}M[/tex]

Hence, the molar solubility of carbon dioxide is [tex]2.63\times 10^{-2}M[/tex]