Respuesta :
Answer:
Part a)
[tex]q = -21.2 \times 10^{-6} C[/tex]
Part b)
[tex]E = 1.02 \times 10^{-7} N/C[/tex]
Explanation:
Part a)
As we know that charge and its sign that remains in equilibrium is under gravity must be such that it will balance the gravitational force by electric force
so here we have
[tex]mg = qE[/tex]
[tex]1.47 \times 10^{-3} (9.81) = q(680)[/tex]
[tex]q = 21.2 \times 10^{-6} C[/tex]
and its sign must be negative so that it will have upward electric force
so it is
[tex]q = -21.2 \times 10^{-6} C[/tex]
Part b)
as we know that weight of proton is balanced by electric force
so we will have
[tex]qE = mg[/tex]
[tex](1.6 \times 10^{-19})E = (1.67 \times 10^{-27})(9.81)[/tex]
[tex]E = 1.02 \times 10^{-7} N/C[/tex]
A. The charge (sign and magnitude) of the particle of mass 1.47 g is –2.12×10¯⁵ C
B. The magnitude of the electric field in which the electric force on the proton is equal in magnitude to its weight is 1.02×10¯⁷ N/C
What is electric field strength?
This is simply defined as the force per unit charge. Mathematically, it is expressed as:
E = F / Q
Where
- E is the electric field strength
- F is the force
- Q is the charge
A. How to determine the charge
- Mass (m) = 1.47 g = 1.47 / 1000 = 1.47×10¯³ Kg
- Electric field strength (E) = 680 N/C
- Acceleration due to gravity (g) = 9.81 m/s²
- Charge (Q) =?
E = F/Q
E = mg / Q
680 = (1.47×10¯³ × 9.81) / Q
Cross multiply
680 × Q = (1.47×10¯³ × 9.81)
Divide both side by 680
Q = (1.47×10¯³ × 9.81) / 680
Q = 2.12×10¯⁵ C
Q = –2.12×10¯⁵ C (since it is stationary)
B. How to determine the electric field strength
- Mass (m) = 1.67×10¯²⁷ Kg
- Acceleration due to gravity (g) = 9.81 m/s²
- Charge (Q) = 1.60×10¯¹⁹ C
- Electric field strength (E) =?
E = mg / Q
E = (1.67×10¯²⁷ × 9.81) / 1.60×10¯¹⁹
E = 1.02×10¯⁷ N/C
Learn more about Coulomb's law:
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