Answer:
Weight of solution produced = 5135 kg
Amount of water removed = 4865 kg
Explanation:
For the balance of mass, the incoming mass of sugar must be equal to the outgoing mass. So, the incoming mass (mi) is 38% of 10000 kg
mi = 0.38x10000 = 3800 kg
The outgoing mass (mo) must be 3800 kg, and it is 74% of the total mass (mt)
mo = 0.74xmt
0.74xmt = 3800
mt = 3800/0.74
mt = 5135 kg
This is the mass of solution produced.
The amount of water removed (wr) is the amount of water incoming (wi) less the amount of water outgoing (wo). Both will be the total mass less the mass of sugar :
wi = 10000 - 3800 = 6200 kg
wo = 5135 - 3800 = 1335 kg
wr = wi - wo
wr = 6200 - 1335
wr = 4865 kg
From the data provided and the concept of balance of mass,, the mass of solution produced is 5135 kg and the water removed is 4865 kg
Evaporation is the process by which molecules of a liquid turn to gas.
To calculate the weight of solution produced and amount of water removed:
Using the concept of balance of mass, the incoming mass of sugar must be equal to the outgoing mass.
Incoming mass (Mi) = 38% of 10000 kg
Mi = 3800 kg
Therefore, the outgoing mass (Mo)= 3800 kg
Mo= 74% of the total mass, Mt
Mo = 0.74 x Mt
Mt = 3800/0.74
Mt = 5135 kg
Thus, the mass of solution produced is 5135 kg
The amount of water removed (Wr) = water incoming (Wi) - water outgoing (wo).
Wi = 10000 - 3800 = 6200 kg
Wo = 5135 - 3800 = 1335 kg
Wr = Wi - Wo
Wr = 6200 - 1335
Wr = 4865 kg
Therefore, the water removed is 4865 kg
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