Answer:
A python3 script is given below
Explanation:
Hi there!
In this program it is assumed that the rectangle will always be parallel to the x and y axis
# First we define three lists where the coordinates will be stored
# The notrect variable will help us if the p1 and p2 coordinates are along the same axis and therefore the will not make a rectangle,in the assumed sense
p1, p2, p3 = [],[],[]
notrect = False
# In this for cycle we ask the user for the coordinates and check if the first two make a rectangle
for i in range(3):
if i<2:
x = float(input('Please write x'+str(i+1)+': '))
y = float(input('Please write y'+str(i+1)+': '))
else:
x = float(input('Please write x: '))
y = float(input('Please write y: '))
if i==0: p1 = [x,y]
elif i==1: p2 = [x,y]
else: p3 = [x,y]
# If they do not make the rectangle we no longer ask for the third and exit the program
if p1 and p2:
if p1[0] == p2[0] or p1[1] == p2[1]:
notrect = True
print('These ponits does not make a rectangle')
break
#If notrect = True we say Bye to the user and nothing else happens
if notrect:
print('Bye')
# If they do make the rectangle we save the x and y coordinates of the rectangle separately, and sort them
else:
x = [p1[0],p2[0]]
y = [p1[1],p2[1]]
x.sort()
y.sort()
# If the x and y coordinates of the third point are between the x and y coordinates of the vertices of the rectangle the last point is indeed inside the rectangle, and print a True. Otherwise, we print a False
print((p3[0]>x[0] and p3[0]<x[1]) and p3[1]>y[0] and p3[1]<y[1])
