An apple falls (from rest) from a tree. It hits the ground at a speed of about 4.9 m/s. What is the approximate height (in meters) of the tree above the ground? The magnitude of the gravitational acceleration g = 9.8 m/s2 Enter your answer in meters. Keep 2 decimal places.

Respuesta :

Answer:

The inicial height of the apple is 1.22 meters

Explanation:

Using the equation for conservarion of mechanical energy:

[tex]E=V+K=constant[/tex]

[tex]K_i=\frac{1}{2}mv_i^2[/tex] where v is the velocity

[tex]V=mgh[/tex]where h is the height

We equate the initial mechanical energy to the final:

Since [tex]v_0=0\ and h_f=0 [/tex]:

[tex]\frac{1}{2}mv_0^2+mgh_0= \frac{1}{2}mv_f^2+mgh_f\\gh_0= \frac{1}{2}v_f^2[/tex]

Solving for h:

[tex]h_0=\frac{4.9^2}{2g}= 1.22 m[/tex]