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A nugget of gold with a mass of 521 g is added to 50.mL of water. The water level rises to a volume of 77.0mL. What is the density of the gold

Respuesta :

moonchilddd

Answer:

19. g/mL

Explanation:

  • First you find the difference between the previous and current water level:

77.0-50.0=27 mL

  • Then you use the formula, density=mass over volume:

d=521g over 27mL or d=521g/27mL

  • Finally, you divide and round to according to it's significant number

=19.2962963 g/mL

turns into 19. g/mL

hoped this helped! (and that its right-_-)

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