find the distance between the points and that is perimiter
find
A to B
B to C
C to A
we need the distance formula
D=[tex] \sqrt{(x2-x1)^{2}+(y2-y1)^{2}} [/tex]
where D is the distance between points (x1,y1) and (x2,y2)
A to B
(-1,-2) to (2,-6)
D=[tex] \sqrt{(2-(-1))^{2}+(-6-(-2))^{2}} [/tex]=5
B to C
(2,-6) to (-3,-6)
since the y value stayed the same, find the distance betwen the x values
2 to -3 is distance of 5
C to A
(-3,-6) to (-1,-2)
D=[tex] \sqrt{(-1-(-3))^{2}+(-2-(-6))^{2}} [/tex]=2√5
add everybody
5+5+2√5=10+2√5 units
