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A wire, of length L = 4.1 mm, on a circuit board carries a current of I = 1.96 μA in the j direction. A nearby circuit element generates a magnetic field in the vicinity of the wire of B = Bxi + Byj + Bzk, where Bx = 4.9 G, By = 2.3 G, and Bz = 2.4 G.
a. Calculate the magnitude of the magnetic field B, in gauss, in the vicinity of the wire due to the circuit element.

Respuesta :

Answer:

The magnitude of the magnetic field B is 5.921 T.

Explanation:

Given that,

Length = 4.1 mm

[tex]B_{x}=4.9\ G[/tex]

[tex]B_{y}=2.3\ G[/tex]

[tex]B_{z}=2.4\ G[/tex]

Current [tex]I = 1.96\ mu A[/tex]

We need to calculate the magnetic field

Using formula of magnetic field

[tex]B=\sqrt{B_{x}^2+B_{y}^2+B_{z}^2}[/tex]

Put the value into the formula

[tex]B=\sqrt{(4.9)^2+(2.3)^2+(2.4)^2}[/tex]

[tex]B=5.921\ T[/tex]

Hence, The magnitude of the magnetic field B is 5.921 T.