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Selena has a quarters, five dimes, and three nickels in her pocket. If one coin is selected at random, what is the probability that it will not be a quarter?
[tex] \frac{1}{4} [/tex]
[tex] \frac{1}{5} [/tex]
[tex] \frac{5}{11} [/tex]
[tex] \frac{1}{2} [/tex]
[tex] \frac{1}{3} [/tex]
​

Respuesta :

sqdancefan

Answer:

  1/2

Step-by-step explanation:

We assume your "a quarters" is a poor speech-to-text rendering of "eight quarters." If so, Selena has 16 coins, of which 8 are not quarters. The probability of choosing a "not quarter" is ...

  8/16 = 1/2 = p(not quarter)

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