Answer:
n(n - 3) + b(n - 3b)
Step-by-step explanation:
n^2 - 3b^2 + nb - 3n =
Rearrange the terms in a way in which you have two terms with a common factor and another two terms with a common factor.
= n^2 - 3n + nb - 3b^2
Now factor a common factor out of each two terms.
= n(n - 3) + b(n - 3b)
Answer:
[tex]n(n-3)+b(n-3b)[/tex]
Step-by-step explanation:
[tex]n^2-3b^2+nb-3n[/tex]
Lets group the terms that has same variables and try to factor
Rearrange the terms
[tex]n^2-3n-3b^2+nb[/tex]
Group first two terms and last two terms
[tex](n^2-3n)+(nb-3b^2)[/tex]
Factor out 'n' from the first group and 'b' from the second group
[tex]n(n-3)+b(n-3b)[/tex]
Here there is no common factor . So this cannot be factored further
