Answer:
1) IF IT IS [tex]\frac{3}{6}+\frac{1}{16}[/tex]: [tex]\frac{9}{16}[/tex]
2) IF IT IS [tex]\frac{3}{8}+\frac{1}{16}[/tex]: [tex]\frac{7}{16}[/tex]
Step-by-step explanation:
1) IF IT IS [tex]\frac{3}{6}+\frac{1}{16}[/tex]:
You can notice that the denominators are not the same. Therefore, the procedure is:
Find the Least Common Denominator (LCD). To find it, descompose each denominator into their prime factors and find the product of the common and non-common with their highest exponent:
[tex]6=2*3[/tex]
[tex]16=2*2*2*2=2^4[/tex]
[tex]LCD=2^4*3=48[/tex]
Now rewrite the LCD as the new denominator, then divide each original denominator by the LCD
Multiply each numerator by the quotient obtained. The sum of these products will be the new numerator.
Finally, reduce the fraction.
Then:
[tex]\frac{3}{6}+\frac{1}{16}=\frac{24+3}{48}=\frac{27}{48}=\frac{9}{16}[/tex]
2) IF IT IS [tex]\frac{3}{8}+\frac{1}{16}[/tex]:
You can notice that the denominators are not the same. Therefore, the procedure is:
Find the Least Common Denominator (LCD). To find it, descompose each denominator into their prime factors and find the product of the common and non-common with their highest exponent:
[tex]8=2*2*2=2^3[/tex]
[tex]16=2*2*2*2=2^4[/tex]
[tex]LCD=2^4=16[/tex]
Now rewrite the LCD as the new denominator, then divide it by each original denominator.
Now rewrite the LCD as the new denominator, then divide each original denominator by the LCD.
Finally, reduce the fraction.
Then:
[tex]\frac{3}{8}+\frac{1}{16}=\frac{6+1}{16}=\frac{7}{16}[/tex]
