Explanation:
It is known that an electron pair represents a domain. Hybridization of [tex]BF_{3}[/tex] will be calculated as follows.
Hybridization = [tex]\frac{1}{2}[\text{Valence electrons of central atom + no. of bonded atoms + negative charge - positive charge}][/tex]
Valence electrons of boron are 3 and no. of bonded atoms in a [tex]BF_{3}[/tex] molecule is 3.
Therefore, calculate hybridization of [tex]BF_{3}[/tex] as follows.
Hybridization = [tex]\frac{1}{2}[\text{Valence electrons of central atom + no. of bonded atoms + negative charge - positive charge}][/tex]
= [tex]\frac{1}{2}[3 + 3 + 0][/tex]
= 3
Hence, hybridization of [tex]BF_{3}[/tex] is [tex]sp^{2}[/tex], that is, trigonal planar.
Thus, we can conclude that the given image represents that it is a trigonal planar molecule with three domains.
