Answer:
Step-by-step explanation:
Let t and c represent the speeds of the train and car (in km/h), respectively. The applicable relationship is ...
time = distance/speed
so we have fir the first trip ...
600/t + 200/c = 17
and for the second trip ...
560/t +240/c = 17.2 . . . . . . 17 hours + 12 minutes = 17.2 hours
These equations can be fairly easily solved using Cramer's rule*:
t = (200·560 -240·600)/(200·17.2 -240·17) = -32000/-640 = 50
c = -32000/(17·560 -17.2·600) = -32000/-800 = 40
The speed of the train is 50 km/h; the speed of the car is 40 km/h.
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* Cramer's rule ordinarily gives a ratio for the variables x=1/t and y=1/c. By inverting that ratio, we can find the values of t and c.
The applicable "Cramer's rule" for ...
is ...