Answer:
7
Step-by-step explanation:
Using Pythagoras' identity on the right triangle
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides.
let x be the other leg, then
x² + 4² = ([tex]\sqrt{65}[/tex] )²
x² + 16 = 65 ( subtract 16 from both sides )
x² = 49 ( take the square root of both sides )
x = [tex]\sqrt{49}[/tex] = 7
That is the other leg is 7 units
To answer this question you must use Pythagorean theorem
[tex]a^{2} +b^{2}=c^{2}[/tex]
a and b are the legs (the sides that form a perpendicular/right angle)
c is the hypotenuse (the side opposite the right angle)
In this case...
a = 4
b = unknown
c = [tex]\sqrt{65}[/tex]
^^^Plug these numbers into the theorem
[tex]4^{2} +b^{2} = √65^{2}[/tex]
Simplify
16 + b² = 65
solve for b
[tex]b^{2}[/tex] + 16 = 65
[tex]b^{2}[/tex] = 49
To completely isolate b you will have to get rid of the square attached to it. To do this you will need to take the square root of both sides
√b² = √49
b = 7
Hope this helped!
~Just a girl in love with Shawn Mendes
