Answer:
57.1 N
Explanation:
The force of friction experienced by the sled is given by:
[tex]F_f = \mu_k N[/tex]
where
[tex]\mu_k = 0.110[/tex] is the coefficient of friction
N is the normal reaction exerted by the snow on the sled
For a flat surface, the normal reaction is equal to the weight of the object:
N = mg
where
m = 53.0 kg is the mass of the sled
g = 9.8 m/s^2 is the acceleration of gravity
Substituting the second equation into the first one, we find:
[tex]F_f = \mu_k m g=(0.110)(53.0)(9.8)=57.1 N[/tex]
