contestada

how much force does it take to push a 62.0 kg dresser at a constant speed across a carpet with µk=0.238. (unit=N)

Respuesta :

Answer:

158.76504N

Explanation:

F = µk * m * g

F = 0.238 * 62 * 9.81

F = 158.76504N

Answer:

Force, F = 144.6 N

Explanation:

It is given that,

Mass of the dresser, m = 62 kg

Coefficient of kinetic friction, [tex]\mu_k=0.238[/tex]

We need to find force with which the dresser is pushed. It is given by :

[tex]F=\mu mg[/tex]

[tex]F=0.238\times 62\times 9.8[/tex]

F = 144.6 N

So, the force taken by the dresser is 144.6 N. Hence, this is the required solution.