Answer:
16π-6cm² or ≈44.265cm²
Step-by-step explanation:
Area of the circle:
πr²
π(4)²
16π
Area of the rectangle:
2*3=6
Subtract the two:
16π-6
For this case we have that the area of the shaded region is given by the subtraction of areas, area of the circle minus the area of the rectangle. That is to say:
[tex]A_ {s} = \pi * r ^ 2-ab[/tex]
Where:
A: It is the radius of the circle
a, b: They are the sides of the rectangle
According to the data we have:
[tex]A_ {s} = \pi * (4) ^ 2-3 * 2\\A_ {s} = \pi * 16-6[/tex]
Taking [tex]\pi = 3.14[/tex]
[tex]A_ {s} = 50.24-6\\A_ {s} = 44.24[/tex]
So, the area of the shaded region is [tex]44.24 \ cm ^ 2[/tex]
Answer:
[tex]44.24 \ cm ^ 2[/tex]
