meredith48034
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the weight of the cars passing over which has a mean of 3550 lb and a standard deviation of 807 pounds. Assume that the waste of the cars pass over the bridge are normally distributed. What is the z-score corresponding to a car that weighs 2800 pounds
a. .789
b. 3.22
c. 3.31
d. -.862​

Respuesta :

mathmate

Step-by-step explanation:

Using the usual notations and formulas,

mean, mu = 3550

standard deviation, sigma = 870  (to be confirmed)

Observed value, X = 2800

We calculate

Z = (X-mu)/sigma = (2800-3550)/870 = -750/879 = -0.862 (to the thousandth)

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