Answer:
0.50 M is the molar concentration of [tex]N_2O_4[/tex].
Explanation:
The equilibrium constant of the reaction = [tex]K_c=5.0\times 10^{-3}[/tex]
[tex]N_2O_4(g)\rightleftharpoons 2NO_2(g)[/tex]
Equilibrium concentration of [tex]NO_2[/tex] = 0.050 M
[tex][NO_2]=0.050 M[/tex]
Equilibrium concentration of [tex]N_2O_4[/tex] = ?
[tex][N_2O_4]= x[/tex]
The equilibrium constant of the reaction is given aSL:
[tex]K_c=\frac{[NO_2]^2}{[N_2O_4]}[/tex]
[tex]K_c=\frac{(0.050 M)^2}{x}=5.0\times 10^{-3}[/tex]
[tex]x = 0.50 M[/tex]
0.50 M is the molar concentration of [tex]N_2O_4[/tex].