Respuesta :

convert to y=ax^2+bx+c form
y+3x-6=-3(x-2)^2+4
exponent
y+3x-6=-3(x^2-4x+4)+4
distribute
y+3x-6=-3x^2+12x-12+4
minus 3x both sides
y-6=-3x^2+9x-8
add 6 both sides
y=-3x^2+9x-2

in form ax^2+bx+c=y
x coordinate of the vertex=-b/2a
and the axis of symmetry is the x coordianat
a=-3
b=9
-9/(2*-3)=-9/-6=3/2

x=3/2 is axis of symmetry

The equation of the axis of symmetry of the graph of y + 3x – 6 = –3(x – 2)2 + 4 would be 3/2.

What is a system of equations?

A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be in one degree.

Given;

[tex]y+3x-6 = -3(x-2)^2+4[/tex]

We need to convert into y =  ax^2+bx+c form

[tex]y+3x-6=-3(x-2)^2+4[/tex]

[tex]y+3x-6=-3(x^2-4x+4)+4[/tex]

[tex]y+3x-6=-3x^2+12x-12+4\\\\y-6=-3x^2+9x-8\\\\y=-3x^2+9x-2[/tex]

By comparing with ax^2+bx+c=y

The x coordinate of the vertex = -b/2a

The axis of symmetry is the x coordinate

a=-3

b=9

-9/(2*-3)

= -9/-6

= 3/2

Hence, x=3/2 is the axis of symmetry.

Learn more about equations here;

https://brainly.com/question/10413253

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