Respuesta :
convert to y=ax^2+bx+c form
y+3x-6=-3(x-2)^2+4
exponent
y+3x-6=-3(x^2-4x+4)+4
distribute
y+3x-6=-3x^2+12x-12+4
minus 3x both sides
y-6=-3x^2+9x-8
add 6 both sides
y=-3x^2+9x-2
in form ax^2+bx+c=y
x coordinate of the vertex=-b/2a
and the axis of symmetry is the x coordianat
a=-3
b=9
-9/(2*-3)=-9/-6=3/2
x=3/2 is axis of symmetry
y+3x-6=-3(x-2)^2+4
exponent
y+3x-6=-3(x^2-4x+4)+4
distribute
y+3x-6=-3x^2+12x-12+4
minus 3x both sides
y-6=-3x^2+9x-8
add 6 both sides
y=-3x^2+9x-2
in form ax^2+bx+c=y
x coordinate of the vertex=-b/2a
and the axis of symmetry is the x coordianat
a=-3
b=9
-9/(2*-3)=-9/-6=3/2
x=3/2 is axis of symmetry
The equation of the axis of symmetry of the graph of y + 3x – 6 = –3(x – 2)2 + 4 would be 3/2.
What is a system of equations?
A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be in one degree.
Given;
[tex]y+3x-6 = -3(x-2)^2+4[/tex]
We need to convert into y = ax^2+bx+c form
[tex]y+3x-6=-3(x-2)^2+4[/tex]
[tex]y+3x-6=-3(x^2-4x+4)+4[/tex]
[tex]y+3x-6=-3x^2+12x-12+4\\\\y-6=-3x^2+9x-8\\\\y=-3x^2+9x-2[/tex]
By comparing with ax^2+bx+c=y
The x coordinate of the vertex = -b/2a
The axis of symmetry is the x coordinate
a=-3
b=9
-9/(2*-3)
= -9/-6
= 3/2
Hence, x=3/2 is the axis of symmetry.
Learn more about equations here;
https://brainly.com/question/10413253
#SPJ5