[tex]\frac{4}{44} =\frac{1\times4}{11\times 4}= \frac{1}{11} = \frac{1\times 7}{11\times 7} = \frac{7}{77}\\\\n= 7[/tex]
Your answer is B.
Another way to solve it is by cross multiplying.
[tex]\frac{4}{44} = \frac{n}{77}\\\\4 \times 77 = 44n\\\\n = \frac{4\times 77}{44}\\\\n = 7[/tex]
Answer is B.