Answer: 49.04
Step-by-step explanation:
Given : Sample size : [tex]n=230[/tex]
Standard deviation : [tex]\sigma=22[/tex]
We know that the standard error of the mean is given by :-
[tex]\text{S.E.}=\dfrac{\sigma}{\sqrt{n}}[/tex]
Then , the standard error of the mean for the given situation will be :-
[tex]\text{S.E.}=\dfrac{230}{\sqrt{22}}\\\\\Rightarrow\text{S.E.}=49.0361647618\approx49.04[/tex]
Hence, the standard error of the mean = 49.04
