Respuesta :
Answer:
No answer is correct.
Explanation:
given data:
Q1 = 400 gpm
P1 = 28 psi
Q2 = ?
P2 = 30 psi
Change in pressure in a pipe is given as
[tex]\Delta P = \frac{32\mu vl}{D^{2}}[/tex]
where v is velocity and it is given as [tex]v = \frac{Q}{A}[/tex]
[tex]\Delta P = \frac{32\mu Ql}{AD^{2}}[/tex]
Therefore, change in pressure is directly proportional to flow
thus we have
[tex]\frac{P_{1}}{Q_{1}}=\frac{P_{2}}{Q_{2}}[/tex]
[tex]Q_{2}=\frac{P_{2}}{P_{1}}*Q_{1}[/tex]
[tex]Q_{2}=\frac{30}{28}*400 = 428.57 gpm[/tex]
[tex]Q_{2} =428.57 gpm[/tex]
no answer is correct
Answer:
428.5 gmp
Explanation:
Given that,
A piping system is operating at quantity = 400 gpm
Pressure = 28 psi
Increased pressure = 30 psi
We need to calculate the resultant flow rate
We know that,
The flow rate is directly proportional to pressure
[tex]Q\propto P[/tex]
Therefore,
[tex]\dfrac{Q_1}{Q_2}=\dfrac{P_1}{P_2}[/tex]
where,
[tex]Q_1\rightarrow 400\text{ gpm}[/tex]
[tex]Q_2\rightarrow x\text{ gpm}[/tex]
[tex]P_1\rightarrow 28\text{ psi}[/tex]
[tex]P_2\rightarrow 30\text{ psi}[/tex]
By substituting into formula
[tex]\dfrac{400}{x}=\dfrac{28}{30}[/tex]
[tex]x=\dfrac{12000}{28}\approx 428.5\text{ gpm}[/tex]
Hence, The resultant flow rate will be 428.5 gmp
