Answer:
10.85 m/s
Explanation:
m = 1200 kg, h1 = 19 m, h2 = 13 m
Let v be the velocity
Use the conservation of energy
Potential energy at 19 m = Potential energy at 13 m + kinetic energy
m x g x h1 = m x g x h2 + 1/2 mv^2
m x g (h1 - h2) = 0.5 x m v^2
g (h1 - h2) = 0.5 v^2
9.8 (19 - 13) = 0.5 x v^2
v = 10.85 m/s
