Answer:
[tex]f(2)=\frac{37}{4}[/tex] or [tex]f(2)=-(-\frac{37}{4})[/tex]
Step-by-step explanation:
we have
[tex]f(x)=2x^{2} +\frac{5}{x+2}[/tex]
Find f(2)
we know that
f(2) is the value of f(x) when the value of x is equal to 2
so
For x=2
substitute
[tex]f(2)=2(2)^{2} +\frac{5}{2+2}[/tex]
[tex]f(2)=8 +\frac{5}{4}[/tex]
[tex]f(2)=\frac{37}{4}[/tex]
or
[tex]f(2)=-(-\frac{37}{4})[/tex]
