Respuesta :

Answer:

[tex]m =-\frac{1}{2}[/tex]

Step-by-step explanation:

The equation of a line in the pending intersection form is:

[tex]y = mx + b[/tex]

Where m is the slope of the line and b is the intersection with the y axis.

In this case we have the following equation

[tex]y-3=-\frac{1}{2}(x-2)[/tex]

To find the slope of this line you must rewrite it in the form

[tex]y = mx + b[/tex]

Then we solve the equation for y.

[tex]y-3=-\frac{1}{2}(x-2)[/tex]

[tex]y=-\frac{1}{2}(x-2)+3[/tex]

[tex]y=-\frac{1}{2}x-2*(-\frac{1}{2})+3[/tex]

[tex]y=-\frac{1}{2}x+1+3[/tex]

[tex]y=-\frac{1}{2}x+4[/tex]

Note that [tex]m =-\frac{1}{2}[/tex]

Finally the slope is: [tex]m =-\frac{1}{2}[/tex]

The slope of the line with equation; y-3 = -1/2(x-2) is; slope, m = -1/2.

According to the question, the equation of the line in discuss is; y-3 = -1/2(x-2).

To determine the slope of the line, we need to rearrange the equation such that it resembles the slope-intercept form of the equation of a straight line as follows;

The equation of a straight line; y = mx + c.

Now, we expand the equation of the line and rearrange as follows;

  • y-3 = (-1/2)x -1

  • y = (-1/2)x -1 + 3

  • y = (-1/2)x + 2.

By comparison, the slope of the line given bey the equation, y-3=-1/2(x-2) is; slope, m = -1/2.

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