Respuesta :
Answer:
Tensile stress is 14.15 N/[tex]mm^{2}[/tex]
Explanation:
When any object is subjected to an external force, the body offers a resisting force which is equal and opposite to the external load. This resisting force is called stress. Thus stress is defined as the force acting perpendicular to the given cross sectional area of the object.
Mathematically, stress , σ = [tex]\frac{force }{area}[/tex]
Given : Tensile force, F = 400 N
Diameter of the rod, d = 6 mm
Area of the rod is given by, A = [tex]\frac{\pi }{4}\times d^{2}[/tex]
= [tex]\frac{\pi }{4}\times 6^{2}[/tex]
=28.27 [tex]mm^{2}[/tex]
Therefore, the tensile tress is, σ = [tex]\frac{force }{area}[/tex]
= [tex]\frac{400 }{28.27}[/tex]
= 14.149 N/[tex]mm^{2}[/tex]
[tex]\simeq[/tex] 14.15 N/[tex]mm^{2}[/tex]
Thus, tensile stress experieced by the rod is 14.15 N/[tex]mm^{2}[/tex]
