Answer:
The vertex (h,k) is (-4,-7).
Step-by-step explanation:
I assume you are looking for the vertex [tex]y=-4(x+4)^2-7[/tex].
The vertex form of a quadratic is [tex]y=a(x-h)^2+k[/tex] where the vertex is (h,k) and a tells us if the parabola is open down (if a<0) or up (if a>0). a also tells us if it is stretched or compressed.
Anyways if you compare [tex]y=-4(x+4)^2-7[/tex] to [tex]y=a(x-h)^2+k[/tex] , you should see that [tex]a=-4,h=-4,k=-7[/tex].
So the vertex (h,k) is (-4,-7).
Answer:
The vertex is [tex](-4,-7)[/tex]
Step-by-step explanation:
The vertex form of a parabola is given by:
[tex]y=a(x-h)^2+k[/tex], where (h,k) is the vertex and [tex]a[/tex] is the leading coefficient.
The given parabola has equation:
[tex]y=-1(x+4)^2-7[/tex]
When we compare to the vertex form, we have
[tex]-h=4\implies h=-4[/tex] and [tex]k=-7[/tex].
Therefore the vertex is (-4,-7)
