For this case we must factor the following equation:
[tex]x ^ 2 + x-6 = 0[/tex]
We must find two numbers that, when multiplied, obtain -6 and when summed, obtain +1. These numbers are: +3 and -2
So, we have to:
[tex](x + 3) (x-2) = 0[/tex]
The roots are:
[tex]x_ {1} = - 3\\x_ {2} = 2[/tex]
ANswer:
[tex](x + 3) (x-2) = 0[/tex]
