PLEASE HELP ME FIND THE AREA OF THIS TRIANGLE
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Answer:
=49.15 cm²
Step-by-step explanation:
To find the area of the triangle we use the sine formula
A= 1/2ab Sin∅
where A is the area a and b are the lengths of two sides that intersect at a point and ∅ is the angle between them.
a=10 cm
b= 12 cm
∅=55°
A= 1/2×10×12×Sin 55
=49.15 cm²
ANSWER
[tex]Area =49.1 {cm}^{2} [/tex]
EXPLANATION
The area of triangle given included angle and length of two sides can be calculated using the formula:
[tex]Area = \frac{1}{2} ab \sin(C) [/tex]
Where C=55° is the included angle and a=12 cm , b=10cm are the known sides.
We plug in these values into the formula to get,
[tex]Area = \frac{1}{2} \times 12 \times 10 \sin(55 \degree) [/tex]
[tex]Area =49 .14912266[/tex]
Rounding to the nearest tenth, the area is
[tex]Area =49.1 {cm}^{2} [/tex]