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Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
Match each graph with the function it represents.

Drag the tiles to the correct boxes to complete the pairs Not all tiles will be used Match each graph with the function it represents class=
Drag the tiles to the correct boxes to complete the pairs Not all tiles will be used Match each graph with the function it represents class=
Drag the tiles to the correct boxes to complete the pairs Not all tiles will be used Match each graph with the function it represents class=

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Gasaqui

Answer:

Graph A → y=√x.

Graph B → y=(√x) - 1.

Graph C → y=√(x-1).

Graph D → y= -√x.

Graph E → y= -√(x-1)

Step-by-step explanation:

The graph 'A' intercepts the y-axis at (0, 0). Therefore it belongs to the function y=√x.

The graph 'D' is exactly the same graph 'A' but reflected across the x-axis. Therefore, it belongs to the function y=-√x.

The function 'C' is exactly the same function y=√x but translated one unit to the right, therefore, the solution function is y=√(x-1)

The graph 'E' is exactly the same graph 'C' but reflected across the x-axis, therefore the function is: y= -√(x-1)

In the options you have two times the function y=√x. I assume that's a mistake. The graph 'B' corresponds to y = (√x) - 1

calculista

Answer:

Part 1) [tex]f(x)=\sqrt{x-1}[/tex] -----> Graph C

Part 2) [tex]g(x)=-\sqrt{x}[/tex] ----> Graph D

Part 3) [tex]h(x)=\sqrt{x}[/tex] -----> Graph A

Part 4) [tex]j(x)=-\sqrt{x-1}[/tex] ---> Graph E

Step-by-step explanation:

Part 1) we have

[tex]f(x)=\sqrt{x-1}[/tex]

Find the domain of the function

The radicand must be positive

so

[tex]x-1\geq 0[/tex]

Solve for x

[tex]x\geq 1[/tex]

The domain is the interval -----> [1,∞)

All real numbers greater than or equal to 1

Find the range

For x=1

[tex]f(1)=\sqrt{1-1}=0[/tex]

so

The range is the interval ----> [0,∞)

All real numbers greater than or equal to 0

therefore

The function represent Graph C

Part 2) we have

[tex]g(x)=-\sqrt{x}[/tex]

Find the domain of the function

The radicand must be positive

so

[tex]x\geq 0[/tex]

The domain is the interval -----> [0,∞)

All real numbers greater than or equal to 0

Find the range

For x=0

[tex]f(0)=-\sqrt{0}=0[/tex]

so

The range is the interval ----> (-∞,0]

All real numbers less than or equal to 0

therefore

The function represent Graph D

Part 3) we have

[tex]h(x)=\sqrt{x}[/tex]

Find the domain of the function

The radicand must be positive

so

[tex]x\geq 0[/tex]

Solve for x

[tex]x\geq 0[/tex]

The domain is the interval -----> [0,∞)

All real numbers greater than or equal to 0

Find the range

For x=0

[tex]f(0)=\sqrt{0}=0[/tex]

so

The range is the interval ----> [0,∞)

All real numbers greater than or equal to 0

therefore

The function represent Graph A

Part 4) we have

[tex]j(x)=-\sqrt{x-1}[/tex]

Find the domain of the function

The radicand must be positive

so

[tex]x-1\geq 0[/tex]

Solve for x

[tex]x\geq 1[/tex]

The domain is the interval -----> [1,∞)

All real numbers greater than or equal to 1

Find the range

For x=1

[tex]f(1)=-\sqrt{1-1}=0[/tex]

so

The range is the interval ----> (-∞,0]

All real numbers less than or equal to 0

therefore

The function represent Graph E

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