Respuesta :
Answer:
Step-by-step explanation:
ANSWER
Point if discontinuity:
{x}= \pm3
Zero of the function is
x = 0
EXPLANATION
The given rational function is:
f(x) = \frac{3x}{ {x}^{2} - 9}
This function is not continous when
{x}^{2} - 9 = 0
{x}= \pm \sqrt{9}
{x}= \pm3
The function is zero when,
3x = 0
x = 0
Answer:
x = 0 is the zero of this function and at x = ±4 function is discontinuous.
Step-by-step explanation:
The given function is [tex]f(x) = \frac{4x}{x^{2}-16}[/tex]
For this function we have to find the discontinuity and zeros of this function.
For zeros of the function [tex]0 = \frac{4x}{x^{2}-16}[/tex]
so zero of the function is x = 0
For x² - 16 = 0 this function not defined therefore, x = ± 4 function will be discontinuous.
Finally, x = 0 is the zero of this function and at x = ±4 function is discontinuous.
