copperhead698
contestada

A girl on a bridge throws a rock
straight down at -12.5 m/s. It hits
the ground 38.4 m below.
How much time did it take?
(Unit = s)
Help please

Respuesta :

aguilerapablo03

t = 1.3 s.

To solve this exercise we have to use the freefall equation t = (v-v₀)/g. v = 0 due the final velocity when the rock reach the ground is 0.

With v₀ = -12.5m/s and g = 9.8m/s²

t = -(-12.5m/s)/9.8m/s²

t = 1.3 s

abidemiokin

The amount of time it will take to reach the ground is 1.3 secs

To get the time it will take, we will use the equation of motion expressed as:

[tex]v =u+gt[/tex]

v is the final velocity

u is the initial velocity

g is the acceleration due to gravity

t is the time taken

Given the following parameters

v = 0m/s

u = -12.5m/s

g = 9.8m/s²

Substitute the given parameters into the formula to get the time taken as shown:

[tex]0=-12.5 + (9.8)t\\12.5 = 9.8t\\t = \frac{12.5}{9.8}\\t = 1.3secs\\[/tex]

Hence the amount of time it will take to reach the ground is 1.3 secs

Learn more here: https://brainly.com/question/8898885

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